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Question

If xy=exy, then find dydx

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Solution

Given xy=exy
Applying logarithm on both sides
lnx+lny=xy
Differentiating on both sides wrt x
1x+1ydydx=1dydx
dydx(1y+1)=11x
dydx×y+1y=x1x
dydx=y(x1)x(y+1)

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