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Question

If xy+yx=1x, y0, the value of x3 + y3 is
(a) 1
(b) –1
(c) 0
(d) -12

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Solution

Given:xy+yx=1x2+y2xy=1x2+y2=xyx2+y2-xy=0 ...1Now,x3+y3=x+yx2+y2-xy Using the identity: a3+b3=a+ba2+b2-ab=x+y×0 From 1=0Hence, the correct option is c.

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