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Question

If xy+yz+zx=1 then find the value of tan1x+tan1y+tan1z.

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Solution

Now,

tan1x+tan1y+tan1z

=tan1(x+y1xy)+tan1z

=tan1(x+y+xxyz1xyyzzx)

=tan1 [ Since xy+yz+zx=1]

=π2

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