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Question

If y=1+1x+1x2+1x3+..... with |x|>1 then dydx=

A
x2y2
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B
y2x2
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C
x2y2
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D
y2x2
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Solution

The correct option is D y2x2
y=1+1x+1x2+1x3+.....y=111x=xx1
dydx=(x1)x(x1)2=1(x1)2×x2x2
dydx=y2x2

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