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Question

If y1/m=[x+1+x2] , then (1+x2)y2+xy1 is equal to :

A
m2y
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B
m2y2
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C
m2y2
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D
my
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Solution

The correct option is A m2y
y=(x+1+x2)m
(1+x2)y1=m(x+1+x2)m
(1+x2)y1=my
(x1+x2)y1+1+x2 y2=my1
(1+x2)y2+xy1=m(1+x2)y1
=m2y

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