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Question

If y=(1+x)(1+x2)(1+x4), then dydx at x=1


A

20

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B

28

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C

1

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D

0

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Solution

The correct option is B

28


y=1+x+x2+x3+x4+x5+x6+x7

dydx |=1+2+3+4+5+6+7=7×82=28

x=1


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