wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If y1(x) is a solution of the differential equation dydx+f(x)y=0, then a solution of differential equation dydx+f(x)y=r(x) is

A
1y(x)y1(x)dx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
y1(x)r(x)y1(x)dx+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
intr(x)y1(x)dx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B y1(x)r(x)y1(x)dx+c
i)dydx+f(x)y1=0f(x)=1y1dy1dxii)dydx1y1dy1dx.y=r(x)e1y1dydxdx=edy1dx=1y1ddx(yy1)=r(x)y1yy1=r(x)dx+cy1y=y1r(x)dxy1+cy1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon