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Question

If y=1x+x22!+x33!+...+xnn! then dydx is equal to

A
y
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B
y+xnn!
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C
yxnn!
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D
y1xnn!
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Solution

The correct option is A y
y=1+x+x22!+x33!+...+xnn!=ex (As it is expansion of ex)

So, y=exdydx=ex=y

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