Question

If $y=2^2{3}^{2x}{5}^{-5}{7}^{-5}$ then $\frac{dy}{dx}=$

Answer 1

$y=2^2{3}^{2x}{5}^{-5}{7}^{-7}y=2^2{5}^{-5}{7}^{-7}{3}^{2x}\frac{dy}{dx}=2^2{5}^{-5}{7}^{-7}{3}^{2x}\log 2x\left(2\right)\frac{dy}{dx}=2^3{5}^{-5}{7}^{-7}{3}^{2x}\log 2x$