By remainder theorem if y = 2 and y = 1 are zeros of the po;unomial
2y3 -5y2 +ay +b then we get zero when we substitute y = 1 and y = 2 into the polynomial.
Substituting y = 1 we get
2(1)3-5(1)2+a(1)+b = 0 => 2-5+a+b=0=>-3+a+b=0 => a+b=3 (1)
Substituting y = 2 we get
2(2)3-5(2)2+a(2)+b = 0=> 2(8)-5(4)+2a+b=0
=> 16-20+2a+b=0 => 2a+b = 4 (2)
Subtract (1) from (2) giving a = 4-3 = 1
so b = 3-a= 3-1=2
Answer: a=1, b=2