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Byju's Answer
Standard XIII
Physics
Basic Differentiation Rule
If y=2 sin2θ+...
Question
If
y
=
2
s
i
n
2
θ
+
t
a
n
θ
, then
d
y
d
θ
will be
A
4
sin
θ
cos
θ
+
sec
θ
tan
θ
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B
2
sin
2
θ
+
sec
2
θ
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C
4
sin
θ
+
sec
2
θ
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D
2
cos
2
θ
+
sec
2
θ
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Solution
The correct option is
B
2
sin
2
θ
+
sec
2
θ
y
=
2
s
i
n
2
θ
+
t
a
n
θ
d
y
d
θ
=
2
×
2
s
i
n
θ
c
o
s
θ
+
s
e
c
2
θ
=
2
s
i
n
2
θ
+
s
e
c
2
θ
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