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Standard Formulae - 1

if y= 2/sin t...

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if y= 2/sin theta + root 3 cos theta ,then minimum value of y is

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y = \frac{2}{s i n θ + \sqrt{3} c o s θ}

, then the minimum value of y is

If y = 2/(sin theta + √3 cos theta), then find the minimum value of y

y = \frac{2}{sin θ + \sqrt{3} cos θ},

then the minimum value of y(

θ \in [0, \frac{π}{2}]

x = 2 cos θ - sin θ; y = cos θ - 3 sin θ,

then the value of

(3 x - y)^{2} + (x - 2 y)^{2}

x {sin}^{3} θ + y {cos}^{3} θ = sin θ cos θ

x sin θ = y cos θ

. Find the value of

x^{2} + y^{2}

.

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