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Question

If y=2x32x2+3x5, then for x=2 and Δx=0.1 value of Δy is

A
2.002
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B
1.9
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C
0
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D
0.9
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Solution

The correct option is B 1.9
Given y=2x32x2+3x5
dydx=6x24x+3
(dydx)x=2=248+3=19
Δy=(dydx)x=2Δx
Δy=19×(0.1)=1.9

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