wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If y=21logx4. Then


A

y=x

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

y=x2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

y=x12

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

y=x3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

y=x12


y=21logx4

Taking log on both sides with base 2

log2y = 1logx4

log2y=log22x {ak=xlogax=k}{x1x>0}

log2y=log4x {logakx=1klogax}

log2y=12log2x

log2y=log2x12

y=x12


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon