If y-2 a 2-b 2 tan -1 a-b a-b tan x 2- a-b-0- thena y 1-1 a-b cos xb y 2-b sin x a-b cos x 2c y 1-1 a-b cos xd y 2-b sin x a-b cos x 2

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Theorems for Differentiability

If y=2 a 2-b ...

Question

If $y = \frac{2}{\sqrt{a^{2} - b^{2}}} \tan^{- 1} (\frac{a - b}{a + b} \tan \frac{x}{2}), a > b > 0$ , then

(a) $y_{1} = \frac{- 1}{a + b \cos x}$
(b) $y_{2} = \frac{b \sin x}{{(a + b \cos x)}^{2}}$
(c) $y_{1} = \frac{1}{a - b \cos x}$
(d) $y_{2} = \frac{- b \sin x}{{(a - b \cos x)}^{2}}$

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Solution

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