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Question

If y=3[x]+1=4[x1]10, then the value of [x+2y]= , , where [ .] denotes GIF.

A
107
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B
107.0
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Solution

Given: y=3[x]+1=4[x1]10
Using GIF property, [x1]=[x]1
3[x]+1=4[x]410
[x]=15
y=3[x]+1=3×15+1=46
2y=46×2=92

We know [x]x<[x]+1
15x<15+1
15+92x+2y<16+92
107x+2y<108
Also, [x+2y]x+2y<[x+2y]+1

Comparing the above two relations we get, [x+2y]=107

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