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Question

If y=3xlogx, then dydx=

A
3xlogx(1+logx)log3
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B
3xlogx(1+logx)
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C
3x(1+logx)log3
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D
(1+logx)log3
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Solution

The correct option is A 3xlogx(1+logx)log3
We have,
y=3xlogx
Differentiate it with respect to x,
dydx=ddx(3xlogx)
=3xlogx×log3×ddx(xlogx) [Using chain rule ]
=3xlogx×log3(xddx(logx)+logxddxx) [Using product rule ]
=3xlogx×log3(xx+logx)
=3xlogx(1+logx)log3

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