Question

If $y=3x^2+2xthen\frac{dy}{dx}$=?

• A. 8x
• B.
• C. 6x + 2
• D. none of these

Answer 1

The correct option is C

6x + 2

$\frac{dy}{dx}=\frac{d}{dx}\left[3x^2\right]+\frac{d}{dx}\left[2x\right]$ (Using the linearity property of differentiation)

$\frac{dy}{dx}=3\frac{d\left[x^2\right]}{dx}+2\frac{d\left[x\right]}{dx}$ (Separating the constant coefficients)
=$3\times 2x^{2-1}+2\times 1x^{1-1}$ =6x+2(using $\frac{d\left[x^n\right]}{dx}=n.x^{n-1}$)