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Resonance

If y = asinx ...

Question

If y = asinx + bcosx , then find dy/dx when tanx = a/b .

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y = {tan}^{- 1} [\frac{a cos x + b sin x}{b cos x - a sin x}]

\frac{d y}{d x}

\frac{d y}{d x}

y = {tan}^{- 1} (\frac{a cos x - b sin x}{b cos x + a sin x}), \frac{a}{b} tan x > - 1

y = {tan}^{- 1} (\frac{a cos x - b sin x}{b cos x + a sin x})

\frac{d y}{d x}

y = a sin x + b cos x

y^{2} + {(\frac{d y}{d x})}^{2}

y = {tan}^{- 1} (\frac{a sin x - b cos x}{a cos x + b sin x}),

\frac{d y}{d x} =

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