If Y-axis is the directrix of the eillipse with eccentricty e=1/2 and corresponding focus is at (3,0), then the equation to its auxiliary circle is
A
x2+y2−8x+12=0
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B
x2+y2+8x+12=0
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C
x2+y2−8x+9=0
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D
x2+y2=4
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Solution
The correct option is Ax2+y2−8x+12=0 Distance between the focus and directrix is ae−ae=3⟹a=2; the center will be ae from directrix that is (4,0).Auxilary circle is (x−4)2+y2=4