Question

If $y=\frac{1}{\log x}$ find $\frac{dy}{dx}$

Answer 1

$y=\frac{1}{\log x}\frac{dy}{dx}=\frac{d}{dx}\frac{1}{\log x}\frac{dy}{dx}=-\frac{1}{(\log x{)}^2}\frac{d}{dx}\log x\frac{dy}{dx}=\frac{-1}{x(\log x{)}^2}$