If y- x4 - x2 - 1x2 - x - 1 and dydx - ax - b- then find a and b -

∴ y=x^2 x+1 Now dydx=2x 1=ax+b⇒ a=2,b= 1 ...

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Derivative from First Principle

If y= x4 + ...

Question

If y= $\frac{x^{4} + x^{2} + 1}{x^{2} + x + 1} a n d \frac{d y}{d x} = a x + b, t h e n f i n d a a n d b .$

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y = \frac{x^{4} + x^{2} + 1}{x^{2} + x + 1}; \frac{d y}{d x} = a x + b F i n d a^{3} + b^{3}

$I f \frac{d}{d x} [\frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}] = a x + b t h e n (a, b) =$

y = \frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}

\frac{d y}{d x} = a x + b

a

b

y = \frac{x^{4} - x^{2} + 1}{x^{2} + \sqrt{3} x + 1}

\frac{d y}{d x} = a x + b

a + b

(\frac{1 + x^{2} + x^{4}}{1 + x + x^{2}}) = a x + b

: (a, b) \equiv

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