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Question

If y=x4+x2+2x2x+1, then dydx=...................

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Solution

y=x4+x2+2x2x+1

dydx=(x2x+1)(4x3+2x)(x4+x2+2)(2x1)(x2x+1)2

=2x53x4+4x3x22x+2x42x3+3x22x+1

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