Question

If $y=\frac{5x^2-3x+4}{1-x},then(1-x)y_3=$

• A. $y_2$
• B. $2y_2$
• C. $3y_2$
• D. $4y_2$

Answer 1

The correct option is C $3y_2$

Given $y=\frac{5x^2-3x+4}{1-x}$

$(1-x)y=5x^2-3x+4$

Differentiating w.r.t. x, we get,

$-y+(1-x)y^{{}^{\prime }}=10x-3$

Differentiating w.r.t. x, we get,

$-y^{{}^{\prime }}-y^{{}^{\prime }}+(1-x)y^{{}^{\prime \prime }}=10$

Differentiating w.r.t. x, we get,

$-2y^{{}^{\prime \prime }}-y^{{}^{\prime \prime }}+(1-x)y^{{}^{\prime \prime \prime }}=0$

$(1-x)y^{{}^{\prime \prime \prime }}=3y^{{}^{\prime \prime }}$