If y=ea cos−1x, −1≤x≤1 show that (1−x2)d2ydx2−xdydx−a2y=0
Given, y=ea cos−1x .....(i)
Differentiating w.r.t. x, we get
⇒ dydx=ea cos−1xddxa cos−1x=ea cos−1x.−a√1−x2⇒ dydx=−ay√1−x2 (∵ ea cos−1x=y)⇒ √1−x2dydx=−ay ....(ii)Again differentiating w.r.t. x,we get√1−x2d2ydx2+dydx.−2x2√1−x2=−a dydx⇒ √1−x2 d2ydx2+(−x√1−x2) dydx=−a(−ay)√1−x2 (Using Eq.(ii))Multiplying throughout by √1−x2,we get (1−x2)d2ydx2−x dydx−a2y=0