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Byju's Answer
Standard XII
Mathematics
Integration of Piecewise Continuous Functions
If y = e x2...
Question
If
y
=
e
(
x
2
+
2
sin
x
)
,
t
h
e
n
d
y
d
x
i
s
A
e
(
x
2
−
2
sin
x
)
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B
e
(
x
2
+
2
sin
x
)
×
(
2
x
+
2
sin
x
)
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C
e
(
x
2
+
2
sin
x
)
×
(
2
x
+
2
cos
x
)
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D
e
x
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Solution
The correct option is
B
e
(
x
2
+
2
sin
x
)
×
(
2
x
+
2
sin
x
)
Applying log on both sides
l
o
g
y
=
(
x
2
+
2
s
i
n
x
)
l
o
g
e
l
o
g
y
=
x
2
+
2
s
i
n
x
Differentiating both sides wrt x
1
y
d
y
d
x
=
2
x
+
2
c
o
s
x
d
y
d
x
=
e
x
2
+
2
s
i
n
x
(
2
x
+
2
s
i
n
x
)
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0
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