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Question

If y=e(x2+2sinx),thendydxis

A
e(x22sinx)
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B
e(x2+2sinx)×(2x+2sinx)
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C
e(x2+2sinx)×(2x+2cosx)
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D
ex
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Solution

The correct option is B e(x2+2sinx)×(2x+2sinx)
Applying log on both sides
logy=(x2+2sinx)loge
logy=x2+2sinx
Differentiating both sides wrt x
1ydydx=2x+2cosx
dydx=ex2+2sinx(2x+2sinx)

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