If y- elog x prove that dy dx -1

Given y=e^logx ⇒ y=x dy/dx=1. ...

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Standard Logarithm

If y= elog ...

Question

If $y = e^{log x}$ prove that $\frac{d y}{d x} = 1$

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y = a^{x^{a^{x^{.^{.^{.^{\infty}}}}}}}

\frac{d y}{d x} = \frac{y^{2} log y}{x (1 - y log x log y)}

y = cos x^{cos x^{cos x^{cos x^{.^{.^{.^{\infty}}}}}}}

\frac{d y}{d x} = \frac{- y^{2} tan x}{1 - y log cos x}

y = sin (l o g_{e} x)

\frac{d y}{d x} = \frac{\sqrt{1 - y^{2}}}{x}

y = c o s^{- 1} (s i n)

\frac{d y}{d x} = - 1

\frac{d y}{d x} = e^{l o g x}

y = \frac{1}{2} log (\frac{1 - cos 2 x}{1 + cos 2 x})

\frac{d y}{d x} = 2 c o sec 2 x

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