If y=ex, then dydx equals
ex2x
xex
2xex
Explanation for the correct option:
Find the dydx.
Given that, y=exDifferentiate the given equation with respect to x.dydx=ex·ddxx[ddxex=ex]=12xex[chainrule]Hence, option (A) is correct.
If x=ey+ey+ey+..., then dydx is equal to