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Question

If y=ex.cotx then dy/dx will be

A
excotxcosec x
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B
ex(cot2xcosec2x)
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C
ex(cotxcosec2x)
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D
excotxcosec2x
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Solution

The correct option is D ex(cotxcosec2x)
y=ex.cotxdydx =exddx(cotx)+cotxddx(ex) =ex(cosec2x)+cotx(ex)=ex[cotxcosec2x]

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