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Byju's Answer
Standard XI
Physics
Basic Differentiation Rule
If y=excotx, ...
Question
If
y
=
e
x
cot
(
x
)
, then
d
y
d
x
will be
A
e
x
cot
(
x
)
−
csc
2
(
x
)
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B
e
x
csc
2
(
x
)
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C
e
x
(
cot
(
x
)
−
csc
2
(
x
)
)
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D
e
x
cot
(
x
)
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Solution
The correct option is
C
e
x
(
cot
(
x
)
−
csc
2
(
x
)
)
y
=
e
x
cot
(
x
)
d
y
d
x
=
e
x
d
d
x
cot
(
x
)
+
cot
(
x
)
d
d
x
e
x
=
e
x
(
cot
(
x
)
−
csc
2
(
x
)
)
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1
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