If y-fax and f-sinx-logex- then find dydx- if it exists- where -2-x-

y = f(a^x) dy/dx= f'(a^x),a^x ln a Put x = log_a sin x dy/dx= f'(sinx)sin x lna dy/dx=ln x sin x ln a ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Chain Rule of Differentiation

If y=fax an...

Question

If $y = f (a^{x})$ and $f^{'} (s i n x) = l o g_{e} x,$ then find $\frac{d y}{d x},$ if it exists, where $\frac{π}{2} < x < π$

Open in App

Solution

Suggest Corrections

Similar questions

y = {c o s}^{- 1} (\frac{s i n x + c o s x}{\sqrt{2}})

\frac{π}{4} < x < \frac{π}{4}

\frac{d y}{d x}

y = cos (sin x^{2}),

x = \sqrt{\frac{π}{2},}

\frac{d y}{d x}

\frac{d y}{d x}

y = log (sec x) 0 \leq x \leq \frac{π}{2}

y = {log}_{e} (x + {log}_{e} (x + . . . .)),

\frac{d y}{d x}

(x = e^{2} - 2, y = \sqrt{2})

\frac{d y}{d x}

y = 12 (1 - cos t), x = 10 (t - sin t), - \frac{π}{2} < t < \frac{π}{2}

Join BYJU'S Learning Program