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Question

If y=f(ax) and f(sinx)=logex, then find dydx, if it exists, where π2<x<π

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Solution

y=f(ax)
dydx=f(ax),axlna
Put x=logasinx
dydx=f(sinx)sinxlna
dydx=lnxsinxlna

1119928_1201858_ans_1c3a79b4398f4b51a48c1e2c8c9f9601.jpg

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