If y=f(f(f(x))) and f(0)=0,f'(0)=1 then dydx at x=0
0
1
-1
2
Find the dydx:
Given that, y=f(f(f(x))) and f(0)=0,f'(0)=1.
Differentiate y with respect to x we have:
dydx=f'ffx
At x=0 :
dydx|x=0=f'ff0=f'f0=f'(0)=1
Hence, option B is correct.