If y = f(x) is symmetric about the lines 3x + 4y + 1 = 0 and 4x – 3y – 7 = 0, then it must be symmetric about
A
(1, 1)
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B
(1, –1)
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C
(0, 0)
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D
(1, 0)
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Solution
The correct option is B (1, –1) If a function is symmetric about two mutually perpendicular lines, it must be symmetric about their point of intersection.