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Question

If y=π5, find the value of 2cosπsin(πy)sin(32π+y)

A
cos25π
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B
cos25π
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C
sin25π
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D
sin25π
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E
tan25π
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Solution

The correct option is C sin25π
Given y=π5
2cosπsin(πy)sin(3π2+y)=2(1)(siny)(cosy)=2sinycosy=sin2y=sin2π5

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