If y=(x2+2x)(3x−4), then dydx=?
none of these
Here u(x)=x2+2x,v(x)=3x−4Using quotient rule,dydx=(3x−4)d(x2+2x)dx−(x2+2x)d(3x−4)dx(3x−4)2=(3x−4)(2x+2−(x2+2x3))(3x−4)2=3x2−8x−8(3x−4)2
If y=[x2+2x3x−4], then dydx=?