Question

If $y={\left(\cos x\right)}^{x^2}$, then $\frac{dy}{dx}$ is equal to

यदि $y={\left(\cos x\right)}^{x^2}$, तब $\frac{dy}{dx}$ का मान है

• A. ${\left(\cos x\right)}^{x^2}\left(\sin x-2x\right)$
• B. ${\left(\cos x\right)}^{x^2}\left(2x\ln \cos x-x^2\tan x\right)$
• C. ${\left(\cos x\right)}^{x^2}\left(-x^2\sin x+2x\cos x\right)$
• D. ${\left(\cos x\right)}^{x^2}\left(x^2\ln \cos x-2x\cos x\right)$

Answer 1

The correct option is B ${\left(\cos x\right)}^{x^2}\left(2x\ln \cos x-x^2\tan x\right)$

Solution