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B
logax+xloga
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C
1xloga+xloga
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D
1xloga−logax(logx)2
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Solution
The correct option is D1xloga−logax(logx)2 y=logax+logxa+logxx+logex+logaa=logxloga+logalogx+1+logalogadydx=1loga1x+loga(−1(logx)2)1x+0+0=1xloga−logax(logx)2