If y - log 1-x2-1 -x2 - then dy-dx then dy-dx is equal to-

Dy/dx=1+x^2/1 x^2× 2x(1+x^2) (1 x^2)/(1+x^2)^2 = 4x/1 x^4 ...

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Formation of a Differential Equation from a General Solution

If y = log 1-...

Question

If $y = l o g (\frac{1 - x^{2}}{1 + x^{2}}), t h e n \frac{d y}{d x}$ then dy/dx is equal to……

$\frac{- 4 x}{1 - x^{4}}$

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$\frac{- 4 x^{3}}{1 - x^{4}}$

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$\frac{1}{4 - x^{4}}$

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$\frac{- 4 x^{3}}{1 - x^{4}}$

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Solution

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Similar questions

y = log (\frac{1 - x^{2}}{1 + x^{2}})

\frac{d y}{d x}

If $y = l o g (\frac{1 - x^{2}}{1 + x^{2}}), t h e n \frac{d y}{d x}$ then dy/dx is equal to……

\frac{d y}{d x}

y = log (\frac{1 - x^{2}}{1 + x^{2}})

\frac{d y}{d x}

y = log (1 + x^{2}) - log (1 - x^{2})

y = x^{2} + \frac{1}{x^{2} + \frac{1}{x^{2} + \frac{1}{x^{2} + . . . \infty}}}

\frac{d y}{d x}

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