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Question

If y=log{log(logx5)}, then find dydx

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Solution

y=log{log(logx5)}
dydx=1log(logx5)1(logx5)
dydx=51xlog(logx5).(logx5)

1213059_1409232_ans_6a4db910171744d194dfdf6f69825779.jpg

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