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Question

If y=log[log(logx)], then value of dydx is.

A
1xlogx
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B
1xlogxlog(logx)
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C
1xlog(logx)
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D
1x
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Solution

The correct option is B 1xlogxlog(logx)
y=log[log(logx)]
Using d(fog(x))dx=d(f(g(x)))dx×d(g(x))dx, we have
dydx=1log(logx)×d[log(logx)]dx
dydx=1log(logx)×1logx×d(logx)dx
dydx=1log(logx)×1logx×1x

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