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Question

If y=loglogx, then eydydx=


A

1x

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B

1xlogx

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C

1logx

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D

ey

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Solution

The correct option is A

1x


Find the dydx:

Given that, y=loglogx

Differentiate y with respect to x using chain rule we get:

dydx=1logx·1x

And y=loglogxey=logx

By substituting value we have:

dydx=1ey·1xeydydx=1x

Hence, option A is correct.


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