Question

If y = log(logx) + $2sinx$, find $\frac{dy}{dx}$

Answer 1

$y=log\left(logx\right)+2sinx$

Differentiate with respect to x

$\frac{dy}{dx}=\frac{1}{logx}\times \frac{1}{x}+2cosx$

$\frac{dy}{dx}=\frac{1}{xlogx}+2cosx$