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Question

If y=log(sinx), find dydx.

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Solution

Given that y=log(sinx), we need to find the value of dydx
We know that the derivative of log(x) w.r.t x is 1x
dydx=ddx(log(sinx))=1sinx×ddx(sinx)=1sinx×cosx=cotx
Hence, dydx=cotx

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