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Substitution

if y=log x^2 ...

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if y=log x^2 base e then the value of dy/dx is

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d x + d y = (x + y) (d x - d y)

then fine the value of log(x+y).

y = log [log (log x)]

, then value of

\frac{d y}{d x}

y = {log}_{e} ({log}_{e} x)

\frac{d y}{d x}

y = e^{sin (log x)}

\frac{d y}{d x} =

y = e^{x log a} + e^{a log x} + e^{a log a}

\frac{d y}{d x} =

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