If y - log x2 - then dydx at x is equal to -

The correct option is E 2e Given, y = ( log x)^2 On differentiating w.r.t. x, we get #160; dydx = 2 log x ×1x At x=e , the value wil ...

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Global Maxima

If y = log ...

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If $y = (log x)^{2},$ then $\frac{d y}{d x}$ at $x$ is equal to :

2

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\frac{e}{2}

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e

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\frac{2}{e}

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2 e

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