Question

If $y=log{x}^x$, find $\frac{dy}{dx}$.

Answer 1

We have, $y=log{x}^x$

$or,y=x\left(logx\right)$

Differentiating on both the side, we have

$\frac{dy}{dx}=\frac{x}{x}+logx$

$or,\frac{dy}{dx}=1+logx$