If y=m1x+c and y=m2x+c are two tangents to the parabola y2+4a(x+a)=0, then
A
m1+m2=0
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B
1+m1+m2=0
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C
m1m2−1=0
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D
1+m1m2=0
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Solution
The correct option is D1+m1m2=0 Given equation of parabola is y2+4a(x+a)=0 ⇒y2=−4a(x+a) Vertex of parabola is shifted a units to the right. Equation of directrix is x=0 i.e. y−axis. Equation of tangents are y=m1x+c y=m2x+c Since these tangents intersect at (0,c) which lies on directrix. Hence tangents are perpendicular. ⇒m1m2=−1 or, m1m2+1=0