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Question

If y=m1x+c and y=m2x+c are two tangents to the parabola y2+4a(x+a)=0, then

A
m1+m2=0
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B
1+m1+m2=0
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C
m1m21=0
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D
1+m1m2=0
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Solution

The correct option is D 1+m1m2=0
Given equation of parabola is
y2+4a(x+a)=0
y2=4a(x+a)
Vertex of parabola is shifted a units to the right.
Equation of directrix is x=0 i.e. yaxis.
Equation of tangents are
y=m1x+c
y=m2x+c
Since these tangents intersect at (0,c) which lies on directrix.
Hence tangents are perpendicular.
m1m2=1
or, m1m2+1=0

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