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Equation of Normal at Given Point

If y=mx+c t...

Question

If $y = m x + c$ touches the parabola $y^{2} = 4 a (x + a)$ then

c = \frac{a}{m}

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c = a m + \frac{a}{m}

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c = a + \frac{a}{m}

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a = \frac{c}{m}

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Solution

The correct option is B $c = a m + \frac{a}{m}$
Parabola: $y^{2} = 4 a (x + a) (a = a, h = - a, k = 0)$
Given tangent: $y = m x + c$
Now condition tangency $=> c = k + \frac{a}{m} - m h$
$=> c = 0 + \frac{a}{m} - m a$
$=> c = m a + \frac{a}{m}$ .

Suggest Corrections

Similar questions

y = m x + c

y^{2} = 4 a (x + a)

a m + \frac{a}{m}

y = m x + c

y^{2} = 4 a (x + a)

y^{2} = 4 a (x + a)

c = m a + \frac{a}{m} .

y = m x + c

y^{2} = 4 a (x + a)

y = m (x + a) + \frac{a}{m}

y^{2} = 4 a (x + a)

m

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