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Question

If y=mx+c touches the parabola y2=4a(x+a), then am+am is equal to

A
y
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B
x
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C
c
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D
None of these.
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Solution

The correct option is C c
Given: Prabola:y2=4a(x+a) 1
Tangent: y=mx+c 2
Condition of tangency c+m×h=k+am, whereh=a,k=0,
c+m(a)=0+am
c=m×a+am
So,a×m+am=c.

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