If y - - 1 -x - 1-x - 1 - sin - 1 -x - 1-x - 1 - then dydx -

y=^ 1 ( √(x)+1√(x) 1 )+sin ^ 1 ( √(x) 1√(x)+1 ) y=cos^ 1 ( √(x) 1√(x)+1 )+sin ^ 1 ( √(x) 1√(x)+1 ) y=π2 ∴dydx=ddx ( π2 )=0 ...

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Variable Separable Method

If y = - 1...

Question

If $y = {sec}^{- 1} (\frac{\sqrt{x} + 1}{\sqrt{x} - 1}) + {sin}^{- 1} (\frac{\sqrt{x} - 1}{\sqrt{x} + 1})$ , then $\frac{d y}{d x}$ =

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Solution

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